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Grade 12th passMagical Mathematics[Interesting Approach]

D expression (1+x),(1+x+x^2),.......(1+x+x^2+....+x^n) r multiplied together and d terms of produt thus obtained r arranged in increasing powers of x in d form of a0+a1x+a2x^2+......, then
1) Hw mny terms r there in prdt
2)find there prdt.

Profile image of Aakanksha Talreja
11 Years agoGrade 12th pass
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1 Answer

Profile image of Askiitians Tutor Team
ApprovedApproved Tutor Answer1 Year ago

To tackle the problem you've presented, let's break it down step by step. We have a product of expressions of the form (1 + x), (1 + x + x²), ..., (1 + x + x² + ... + xⁿ). The first thing we need to do is understand how many terms are in the product and then find the product itself. Let's dive into it!

Understanding the Expressions

The expressions you provided can be rewritten in a more manageable form. Each expression can be represented as a geometric series. For instance:

  • The first term is (1 + x), which has 2 terms.
  • The second term is (1 + x + x²), which has 3 terms.
  • The third term is (1 + x + x² + x³), which has 4 terms.
  • And so on, up to (1 + x + x² + ... + xⁿ), which has (n + 1) terms.

Counting the Terms in the Product

To find the total number of terms in the product of these expressions, we need to consider how many ways we can select terms from each factor. Each factor contributes a certain number of choices:

  • From (1 + x), we can choose either 1 or x (2 choices).
  • From (1 + x + x²), we can choose 1, x, or x² (3 choices).
  • From (1 + x + x² + x³), we can choose 1, x, x², or x³ (4 choices).
  • Continuing this pattern, the last factor (1 + x + ... + xⁿ) gives us (n + 1) choices.

Thus, the total number of terms in the product is the product of the number of choices from each factor:

Total Terms = 2 × 3 × 4 × ... × (n + 1)

This can be expressed as:

Total Terms = (n + 1)! / 1!

Finding the Product

Now, let’s find the actual product of these expressions. The product can be expressed as:

P(x) = (1 + x)(1 + x + x²)(1 + x + x² + ... + xⁿ)

Each expression can be simplified using the formula for the sum of a geometric series:

(1 + x + x² + ... + x^k) = (1 - x^(k + 1)) / (1 - x) for k = 0 to n.

Thus, we can rewrite the product as:

P(x) = (1 - x^2) / (1 - x) × (1 - x^3) / (1 - x) × ... × (1 - x^(n + 1)) / (1 - x)

Factoring out the common denominator, we have:

P(x) = (1 - x^2)(1 - x^3)...(1 - x^(n + 1)) / (1 - x)^(n + 1)

Final Thoughts

In summary, we have determined that the total number of terms in the product is (n + 1)! and the product itself can be expressed in a simplified form involving the geometric series. This approach not only helps in understanding the structure of the product but also provides a clear pathway to calculate it for any value of n.